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2 years ago

Determine the center and radius of the following circle equation: x? + y2 - 2x - 12y +36 = 0

Mathematics

2 answers:

PolarNik [594]2 years ago

6 0

Answer:

The center is at (1, 6) and the radius is 1.

Step-by-step explanation:

x^2 + y^2 - 2x - 12y +36 = 0

Convert to standard form:

x^2 - 2x + y^2 - 12y = -36

(x - 1)^2 - 1 + (y - 6)^2 - 36 = -36

(x - 1)^2 + (y - 6)^2 = -36 + 36 + 1

(x - 1)^2 + (y - 6)^2 = 1

The center is at (1, 6) and the radius is 1.

Gre4nikov [31]2 years ago

3 0

Step-by-step explanation:

x²+ y² -12x - 18y +17 = 0 means : (x²-12x+36)-36+(y²-18y+81)-81-27 =0

(x-6)²+(y-9)² =12²....standard form when the center is (-6 , 9) and radius 12

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An airplane is flying at a speed of 500 mi/h at an altitude of one mile. The plane passes directly above a radar station at time

d1i1m1o1n [39]

Answer:

a) $s=\sqrt{1+d^2}$

b)d(t)=500t

c) $s(t) =\sqrt{1+250000t^2}$

Step-by-step explanation:

d = Horizontal distance

s = the distance between the plane and the radar station

The horizontal distance (d), the one mile altitude, and s form a right triangle.

So, use Pythagoras theorem

$Hypotenuse^2=Perpendicular^2+Base^2$

$s^2=1^2+d^2$

a) $s=\sqrt{1+d^2}$

(b) Express d as a function of the time t (in hours) that the plane has flown.

$distance = speed \times time$

d(t)=500t

$s(t) =\sqrt{1+d^2}$

using b

$s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}$

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3 years ago

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ratelena [41]

Answer:

C: x≥12

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Step-by-step explanation:

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I’m not too sure of what the equation is but I made a guess let me know if this was the right equation please I can redo it.

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You would either add or subtract the 3 on both sides.

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Step-by-step explanation:

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