The formula for this is
![A=2 \pi rh+2 \pi r^{2}](https://tex.z-dn.net/?f=A%3D2%20%5Cpi%20rh%2B2%20%5Cpi%20%20r%5E%7B2%7D%20)
. If the diameter is 8 the radius is 4, so filling in accordingly we have
![A=2 \pi (4)(12)+2 \pi (16)](https://tex.z-dn.net/?f=A%3D2%20%5Cpi%20%284%29%2812%29%2B2%20%5Cpi%20%2816%29)
and
![A=96 \pi +32 \pi](https://tex.z-dn.net/?f=A%3D96%20%5Cpi%20%2B32%20%5Cpi%20)
which is
![A=128 \pi](https://tex.z-dn.net/?f=A%3D128%20%5Cpi%20)
and when you multiply in 3.14 you get that A = 401.92 or B above.
Answer:
Option C. 4(20-16y): Each side measures 20-16y units.
Step-by-step explanation:
we know that
The perimeter of a square is equal to
![P=4b](https://tex.z-dn.net/?f=P%3D4b)
where
b is the length side of the square
we have
![P=(80-64y)\ units](https://tex.z-dn.net/?f=P%3D%2880-64y%29%5C%20units)
substitute the given value in the formula
![(80-64y)=4b](https://tex.z-dn.net/?f=%2880-64y%29%3D4b)
solve for b
Divide by 4 both sides
![(20-16y)=b](https://tex.z-dn.net/?f=%2820-16y%29%3Db)
Rewrite the expression
![b=(20-16y)\ units](https://tex.z-dn.net/?f=b%3D%2820-16y%29%5C%20units)
<em>Alternative Method</em>
we have
![P=(80-64y)\ units](https://tex.z-dn.net/?f=P%3D%2880-64y%29%5C%20units)
Factor 4
![P=4(20-16y)\ units](https://tex.z-dn.net/?f=P%3D4%2820-16y%29%5C%20units)
so
Each side measures (20-16y) units.
It would go along with, "if I get better grades, then I study."