Please indicate exponentiation using " ^ " Thanks.
f(x)=x2+14x+40 => <span>f(x)=x^2+14x+40
Next, complete the square:
</span>f(x)=x^2+14x+ 49 - 49 +40 = (x+7)^2 - 9
Write this in the form y = (x+7)^2 - 9 or y + 9 = (x+7)^2
Comparing this result to y = a(x-h)^2 + k, we see that h = -7 and k=-9
In vertex form, the equation is y + 9 = (x+7)^2 and the vertex is at (-7, -9).
Yes!
- you applied the distributive property
- combined like terms
- and answered the rest right!
Answer:
12
Step-by-step explanation:
Using the pythagorean theorem, we know that a^2+ b^2=c^2
In our case, we know b, which is 5 and c which is 13.
If we plug that into the equation, we get a^2+ 5^2 = 13^2
Next, we simplify the equation. a^2 + 25 = 169
Then we subtract 25 from 169. 169 - 25 = 144.
Lastly, we do the square root of 144 and we get 12 which is the missing side.
3pi/7 < pi/2 because 3/7 < 1/2, and pi/2 is a right angle. Conclusion: the angle opposite side a is an acute angle. In this situation the triangle could be a right triangle, in which case C would be true, but it does not have to be a right triangle, so don´t choose C. Similarly, it could be an acute triangle, in which case B would be true, but it does not have to be, so don´t choose B. Also, A says the angle opposite side a is obtuse, which is false. So don´t choose A. That leaves D, which says the angle opposite side a is acute, which we know is true. So the answer is <span>D. b^2 + c^2 > a^2</span>
