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3 years ago

PLEASE HELP JUST KINDA CONFUSED ON THIS ONE I WILL MARK AS BRAINLIEST

Mathematics

2 answers:

WARRIOR [948]3 years ago

4 0

Answer:

1 milliliter is 20 drops.

Fynjy0 [20]3 years ago

3 0

Answer:

1 mililiter = 20 drops

Step-by-step explanation:

<h2><em><u>multiply the volume value by 20</u></em></h2><h2><em><u /></em></h2>

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)Tessa had $35. She bought a book for $7 and a magazine for $5. Which expression correctly shows the total money Tessa has left?

Sergeu [11.5K]

Total - book $ - magazine $

Which is equal to:

Total + (-book $) + (-magazine $)
$35 + (-$7) + (-$5)

ANSWER: (C) $35 + (-$7) + (-$5)

Hope this helps! :)

4 0

3 years ago

Which of the following correctly names a side of the triangle below?

slamgirl [31]

Answer:

C. $\frac{}{AB}$

Step-by-step explanation:

You can solve this in two ways, firstly by eliminating all the wrong answers, and secondly by just knowing that the horizontal line in $_$ $\frac{}{AB}$ means that we are talking about a line.

This is how we solve this question by using the eliminating process.

(A. ∠C) is not the right answer because the ∠ sign lets us know that this answer represents an angle, not a line

(B. <em>B) </em>is not the right answer because it represent a point, not a line (in math we use a singular capital letter to represent points)

(D. ΔABC) is not the right answer because the Δ sign lets us know that the answer represents a triangle, not a line.

Therefore, the only option left is C. $\frac{}{AB}$

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

Please hurry !!!!!!!!!!!!!!!!!

Elan Coil [88]

I think it may be: 0.66666666666

I only looked it up on the internet.

7 0

3 years ago

What is the area of this figure? <br><br> Enter your answer in the box.

ale4655 [162]

Answer:

42 units squared

Step-by-step explanation:

break it up into smaller shapes. if you split the big shape at y = 2 and at y=-2, you'll get two triangles and one rectangle.

so the area of the rectangle = l x w

= 4 x 7

= 28

the area of the triangle is ( l x w )/2

= (7 x 2)/2

= 7

the other triangle is the same too

so the area of that is also 7.

now add all areas,

7+7+28 = 42

8 0

3 years ago

Read 2 more answers