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Whitepunk [10]
3 years ago
7

Hat is the greatest common factor of 20 and 36? 2 4 5 6

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0
4 is the GCF of 20 and 36
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I WILL MARK U BRAINLIEST PLEASE HELP
larisa86 [58]

Answer:

x is 0

y is 3

Step-by-step explanation:

Did this before in 7th grade

8 0
3 years ago
Kylie is planning to provide online science and Chinese language tutoring sessions. The sciences
Ivahew [28]

Answer:

120 ≤ 20c + 40s

Step-by-step explanation:

(Assuming her name is Kylie, who is giving 40 minute science sessions and 20 minute Chinese sessions.)

The unit for time will be minutes.

Write an equation for time needed for science sessions

40s = t

Write an equation for time needed for Chinese sessions

20c = t

Combine the two equations for the total time.

20c + 40s = total time

She does not want the total time to be more than two hours.

Convert two hours to minutes. There are 60 minutes in an hour.

2h * 60mins = 120 mins

Therefore t ≤ 120. Include this into the equation.

120 ≤ 20c + 40s

8 0
3 years ago
Find the total surface area of this triangular prism 8cm 30cm 24cm 7cm
Alenkinab [10]

Answer:

61

Step-by-step explanation:

6 0
3 years ago
Suppose that theta is an angle in standard position whose terminal side Intersects the unit circle at (-11/61, -60/61)
Blizzard [7]

Answer:

The exact values of the tangent, secant and cosine of angle theta are, respectively:

\cos \theta = -\frac{11}{61}

\tan \theta = \frac{-\frac{60}{61} }{-\frac{11}{61} } = \frac{60}{11}

\sec \theta = \frac{1}{-\frac{11}{61} } = -\frac{61}{11}

Step-by-step explanation:

The components of the unit vector are x = -\frac{11}{61} and y = -\frac{60}{61}. Since r = 1, then x = \cos \theta and y = \sin \theta. By Trigonometry, tangent and secant can be calculated by the following expressions:

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}

\sec \theta = \frac{1}{\cos \theta} = \frac{1}{x}

Now, the exact values of the tangent, secant and cosine of angle theta are, respectively:

\cos \theta = -\frac{11}{61}

\tan \theta = \frac{-\frac{60}{61} }{-\frac{11}{61} } = \frac{60}{11}

\sec \theta = \frac{1}{-\frac{11}{61} } = -\frac{61}{11}

3 0
3 years ago
Is 0.75 a solution for n < 1
attashe74 [19]
Yes it could be one........
7 0
3 years ago
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