Answer:
The shelter can house 17 cats because
17 < 28.
Step-by-step explanation:
We cannot have fractions of cats, and we cannot have a negative number of cats. So the third statement is reasonable because c < 28.
Perimeter = 2L + 2W → 240 = 2L + 2W → 120 = L + W → 120-L = W
Area = L x W → Area = L(120-L) → Area = 120L - L²
Find the derivative: dA/dL = 120 -2L → 0 = 120 - 2L → L = 60
Area = 120L - L² = 120(60) - (60)² = 7200 - 3600 = 3600
The maximum area is 3600 yds²
That'd be 10^3 * 6*10^(-3), or just 6.