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dem82 [27]
3 years ago
5

Rancher juan wants to enclose a rectangular area beside a river. there are 240 yards of fencing available. what is the largest t

otal area that can be enclosed?
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0
Perimeter = 2L + 2W →  240 = 2L + 2W  →  120 = L + W  → 120-L = W
Area = L x W  → Area = L(120-L)  →  Area = 120L - L²
Find the derivative:
dA/dL = 120 -2L → 0 = 120 - 2L → L = 60

Area = 120L - L² = 120(60) - (60)²  = 7200 - 3600 = 3600

The maximum area is 3600 yds²
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Solution:

Given:

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The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

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Hence,

\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\  \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\  \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

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1 year ago
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Hunter-Best [27]

Answer:

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Step-by-step explanation:

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(256-16)/(4-2) = 240/2 = 120

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