Ugh, more algebra pretending to be geometry. Why?
This is a pretty awful instance of the genre, with no units on the constant 16, assumed to be degrees.
The total arc measure in a circle is 360 degrees. Geometry part over.
3m + 16 + 2m + 3m = 360
8m = 344
m = 344/8 = 43
Arc measures:
Arc 3m+16 = 3(43)+16 = 145°. The angle subtended by that arc is half that, 145/2=72.5°
Arc 2m=2(43)=86°. The angle subtended is half that, 43°
Arc 3m=3(43)=129°. The angle subtended is half that, 64.5°
Answer:
Step-by-step explanation:
y + 2 = 7(x - 2)
y + 2 = 7x + 14
y = 7x + 12
Answer:
a) For the 90% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Answer:
12
Step-by-step explanation:
Answer:
a believe it is c..........
