2(3 + 3y) + y = 11
First, apply the distributive property:
2(3 + 3y) + y = 11
6 + 6y + y = 11
6 + 7y = 11
Substract 6 from both sides:
6 - 6 + 7y = 11 - 6
7y = 5
Divide both sides by 7:
Answer:
P = 9 is the max value
Step-by-step explanation:
Sketch
2x + 4y = 10
with x- intercept = (5, 0) and y- intercept (0, 2.5)
x + 9y = 12
with x- intercept = (12, 0) and y- intercept = (0, )
Solve
2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)
The region corresponding to the solution of the system of constraints
Has vertices at (0, ), (0, 0) , (5, 0) and (3, 1)
Now evaluate the objective function at each vertex.
(0, 0) can be excluded as it will not give a maximum
(5, 0) → P = 5 + 0 = 5
(0, ) → 0 + 8 = 8
(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value
Thus the maximum value is 9 when x = 3 and y = 1