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Brilliant_brown [7]
3 years ago
10

On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 4, negative 4), and goes

through (negative 2, 0). The graph of the function f(x) = (x + 6)(x + 2) is shown. Which statements describe the graph? Check all that apply. The vertex is the maximum value. The axis of symmetry is x = –4. The domain is all real numbers. The function is increasing over (–∞, –4). The function is negative over (–6, –2).
Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Answer:The axis of symmetry is x=-4

The domain is all real numbers

The function is negative over (-6,-2)

Step-by-step explanation:

Its right

kkurt [141]3 years ago
7 0

Answer:

  • The axis of symmetry is x = –4.  (B)
  • The domain is all real numbers. (C)
  • The function is negative over (–6, –2). (E)

Step-by-step explanation:

These are the actual answers. I just did it on E 2020. You are welcome.

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3 years ago
Lim<br> x-&gt;infinity (1+1/n)
FrozenT [24]

Answer:

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1

Step-by-step explanation:

We want to evaluate the following limit.


^{ \lim}_{n \to \infty} (1+\frac{1}{n})


We need to recall that, limit of a sum is the sum of the limit.


So we need to find each individual limit and add them up.

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}


Recall that, as n\rightarrow \infty,\frac{1}{n} \rightarrow 0 and the limit of a constant, gives the same constant value.



This implies that,


^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0


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^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1


The correct answer is D



5 0
3 years ago
How to solve question one ?
viva [34]
-30-5x=-4x-6(5+4x)

First, you need to use the distributive property on the right to get -30-5x=-4x-30-24x

Then, you can add like terms to get -30-5x=-30-28x

Then, you can add 30 to both sides and add 5x to both sides to get 0=-23x

Finally, you divide both sides by -23 to get 0=x
6 0
3 years ago
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