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Alex787 [66]
3 years ago
13

PLEASE ANSWER FAST!! FIRST CORRECT ANSWER MARKED BRAINLIST. I NEED TO PASS THIS CLASS

Mathematics
2 answers:
Inessa05 [86]3 years ago
5 0
The answer is 6900%!!!
soldier1979 [14.2K]3 years ago
3 0

Answer:

6900%

Step-by-step explanation:

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Dont leave any links please
Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

\displaystyle \large{ {(mn)}^{b} =  {m}^{b} {n}^{b}   } \\  \displaystyle \large{ {n}^{ - b} =   \frac{1}{ {n}^{b} }    }

We are given the expression:

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } }

Use the first law of exponent above.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) }   } \\  \displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } {n}^{  - 1}   }

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\   \displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =  {m}^{2 } ( \frac{1}{ {n} } )} \\

Multiply m in.

\displaystyle \large{( {m}^{8}  {n}^{ - 4} )^{ \frac{1}{4} } =   \frac{ {m}^{2} }{ {n} } }

Thus the answer is m^2/n.

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3 years ago
Translate into mathematical phrase.the weight (w) is more than 2kg​
Ludmilka [50]

Answer:

w>2kg

Step-by-step explanation:

the weight is greater than 2kg.

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3 years ago
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