Answer:
The figure is not a square, because:
The diagonals DO NOT intersect at their midpoints.
The diagonals are NOT of the same length.
The diagonals are NOT perpendicular.
Step-by-step explanation:
✍️If two diagonals intersect at their midpoints, the coordinates of their midpoints will be the same.
Find the midpoints of diagonal AC and BD using the midpoint formula,
.
Midpoint (M) of AC, for A(-4, -6) and C(6, -18):



Midpoint of diagonal AC = (1, 12)
Midpoint (M) of BD, for B(-12, -12) and D(13, -1):


Midpoint of diagonal BD = 
The coordinates of the midpoint of diagonal AC and diagonal BD are not the same, therefore, the diagonals do not intersect at their midpoints.
✍️Use distance formula to calculate the length of each diagonal to determine whether they are of the same length.
Distance between A(-4, -6) and C(6, -18):




(nearest tenth)
Distance between B(-12, -12) and D(13, -1):




(nearest tenth)
Diagonal AC and BD are not of the same length.
✍️If the diagonals are perpendicular, the product of their slope would equal -1.
Slope of diagonal AC:
A(-4, -6) and C(6, -18)

Slope of diagonal BD:
B(-12, -12) and D(13, -1)

Product of their slope:
The product of their slope doesn't equal -1. Therefore, diagonal AC and BD are not perpendicular to each other.