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ale4655 [162]
3 years ago
8

Dexter earns no less than 50$,but no more than 100$.which inequality can be used to represent his earnings,e?

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

50$<x<$100

Step-by-step explanation:

more then 50$ is x>$50

les then $100 is x<$100

x> means x is bigger then...

x< means x is smaller then...

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A cylindrical well has a radius of 8 feet and a height of 13 feet what is the volume of the well use 3.14 for pie round your ans
vitfil [10]
To find the volume of a cylinder, you use this formula:
V = \pir^{2}h

Plug in your numbers,
V = (3.14 * 8^{2}) * 13

Exponents:
V = (3.14 * 64) * 13

Parentheses:
V = 200.96 * 13

Multiply:
V = 2612.48ft^{2}
8 0
3 years ago
Carrie missed 9.6% of the problems on a test. The test had a total of 125 problems.
Nataly_w [17]

Answer:

G 13

Step-by-step explanation:

X/125 = 9.6%/100%

125*(9.6) / 100 = 12;

BEST estimate 13

7 0
2 years ago
What are the soulutions of x^2+6x-6=10?
tia_tia [17]

Answer:x= -8 or 2

Step-by-step explanation:

6 0
3 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
The standard form of the equation of a circle is (x−3)^2+(y−1)^2=16.
aivan3 [116]
So the answer is A.......

7 0
3 years ago
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