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anyanavicka [17]
3 years ago
15

Compare fractions and mixed numbers

Mathematics
2 answers:
slamgirl [31]3 years ago
6 0
A fraction can be improper 
Ex: 3/2
While a mixed fraction is a neater way of writing a fraction
3 1/2
Mumz [18]3 years ago
6 0
Fractions are simply one number over another number. They are a way to express decimal numbers between 0 and 1. To find the value, just divide the numerator (top number) by the denominator (bottom number). For example:

\frac{1}{2} is the fraction one-half. It has a value of 0.5.

Mixed numbers are similar to fractions, however they also have an integer element in addition to the fraction.They are used to express numbers that have a decimal in them, but that can be larger than 1. For example:

1 \frac{1}{2} is a mixed number that represents 1.5. It is the whole number 1 added to the fraction one-half.

Another type of fraction is the improper fraction. It is how you write a mixed number as a single fraction. To write an improper fraction, multiply the denominator of the  fraction by the whole number, then add the numerator. The improper fraction is this result over the same denominator. For example:

31 \frac{1}{2} = \frac{7}{2}

The mixed number is converted to an improper fraction by multiplying the 3 and 2, then adding 1. The  result of 7 is divided by 2.
You might be interested in
The average high temperature each month in a calendar year for a city in South Carolina is represented by the function: f(x)=−x2
LuckyWell [14K]

Answer:

Average\hspace{3}rate\hspace{3}of\hspace{3}change=-7.7

Step-by-step explanation:

The average rate of change measures the average rate at which a function changes per unit time in a given interval. In another words, the average rate of change is the relationship between vertical and horizontal changes between two points of the function. So, basically if you are trying to find the average rate of change, you are trying to find the slope.

Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=m=\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1}

If x represents the months, then:

Let:

September=x_1=9\\December=x_2=12

So:

For:

f(x)=-x^2+13.3x+42

f(x_1)=f(9)=-(9)^2+13.3(9)+42=80.7\\\\f(x_2)=f(12)=-(12)^2+13.3(12)+42=57.6

Therefore:

Average\hspace{3}rate\hspace{3}of\hspace{3}change=\frac{57.6-80.7}{12-9} =\frac{-23.1}{3} =-7.7

4 0
4 years ago
Can anyone please help with this?
lapo4ka [179]

Answer:

Yes I can :O

Mean: About 11.87

Median: 11

Mode: 10

Step-by-step explanation:

Mean: Add up all the numbers and divide by the total number of numbers

<em>*deep breath in haha*</em>

6+7+7+8+8+9+9+9+50 (the 10s)+33 (the 11s)+12+12+12+12+13+14+14+16+16+17+17+18+18+19=356

356 (total) / 30 (number of numbers) = 11.8666666666666666666666 etc = 11.87

Median: With all the numbers in order, the middle number (if there are two add them together and divide by 2)

Not much to show, just mark them off starting from the outside getting inside, you end up with 11!

- See attached

Mode: Data value that occurs most often, in this case we can see that 10 happened the most

Hope this helps, have a nice day! :D

4 0
3 years ago
Try To Solve It<br> And If Right I give thanks and 5 star rate
valina [46]
The answer is A or I
8 0
3 years ago
How do you begin to solve x^3-3x^2 &gt; x-3?
aliya0001 [1]
For any polynomial, first check to see if it factors. Then you can set each factor equal to zero.
x^3 -3x^2 -x+3 \ \textgreater \  0 \\  \\ x^2 (x-3) - (x-3) \ \textgreater \  0 \\  \\ (x^2 -1)(x-3) \ \textgreater \  0 \\  \\ (x-1)(x+1)(x-3) \ \textgreater \  0

The three zeros are -1,1,3

Next plug in values in each interval between zeros to test whether its greater than 0.

Try x values: -2,0,2,4

x = -2 yields a negative result, the interval x< -1 is Not a solution.

x = 0 yields a positive result, the interval -1
x = 2 yields a negative result, the interval 1
x = 4 yields a positive result, the interval x>3 IS a solution
4 0
3 years ago
4 × (1,351 - 381)
ValentinkaMS [17]
The answer to this question is c. Hope I was able to help
5 0
4 years ago
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