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alexandr402 [8]
4 years ago
14

If log w = (1/2) log x + log y, then w= ?

Mathematics
2 answers:
sweet [91]4 years ago
8 0
That’s my answer ! I hope it help

alina1380 [7]4 years ago
6 0

Answer:

w = \sqrt{x} y

Step-by-step explanation:

Formula used :

a \ log\ b = log \ b^a\\\\log a + log b = log \ ab

 

log\ w = \frac{1}{2} log\ x + log \ y\\\\log \ w = log \sqrt{x}  + log \ y\\\\log \ w = log \sqrt{x}  y\\\\w = \sqrt{x} y

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777dan777 [17]
If I can see what the angles look like I will be able to know! Add a picture where it shows the picture of the angles!
4 0
3 years ago
Child admission is $5.70 and adult admission is $9.50. Twice as many adult tickets ad child tickets were sold. for a total of $5
makkiz [27]
Let the number of child tickets sold be x, and number of adult tickets be y, then
5.70x + 9.50y = 543.40 . . . (1)
y = 2x . . . (2)

Putting (2) into (1), gives
5.7x + 9.5(2x) = 543.4
5.7x + 19x = 543.4
24.7x = 543.4
x = 543.4/24.7 = 22

Therefore, 22 child tickets were sold.
4 0
4 years ago
A sliver of gold has a volume of 0.678 cm3. What is the mass of this sliver of gold?
Aliun [14]

Answer - 13.098 gm

Description -

Dear student,

As we know Density= \frac{Mass}{Volume}

⇒ Mass = Density * Volume

so multiplying given Volume with the Density of gold ,we can calculate the mass of the gold . Density of gold at room temp. is 19.32 grams per cubic centimeter.

so mass of the sliver of gold = 19.32 * 0.678 = 13.098 (ans)


5 0
3 years ago
During a tropical storm, the temperature decreased from 84° to 63º. Find the percent decrease in temperature during the storm. (
kipiarov [429]

Answer:

b

Step-by-step explanation:

b is the answer

3 0
3 years ago
Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ<2π. secant StartFraction 5 theta Over 4 En
qaws [65]

Answer:  4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

sec 5\theta/4 =2

Recall that sec \theta = 1/cos \theta

1/cos (5\theta/4) =2

cos (5\theta/4) =1/2

Cos^{-1} \frac{1}{2} = 5\theta/4

This implies that

\mp60+360n=5\theta/4

\theta=4/5(\mp60+360n)= \mp48+288n

When  n=0, \theta=48

When  n=1, \theta=240, 336

Therefore the values of \theta between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0
3 years ago
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