If log w = (1/2) log x + log y, then w= ?
2 answers:
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Take the numerator of the fraction and factor it out.
Your fraction should now look like this:
Because (x+4) is present in both the numerator and denominator, you can cross it out. You should be left with only (x-1) in the numerator.
x cannot equal -4, as if it is inputted in the denominator, -4 + 4 would equal 0. Dividing by 0 is impossible.
Your fraction should now look like this:
Because (x+4) is present in both the numerator and denominator, you can cross it out. You should be left with only (x-1) in the numerator.
x cannot equal -4, as if it is inputted in the denominator, -4 + 4 would equal 0. Dividing by 0 is impossible.
Answer:
b
Step-by-step explanation:
c11 = (-1) *3 + (-3)*2 + 2*(-4) = -3 - 6 - 8 = -17
C12 = (-1)*3 + (-3)*(-5) + 2*(-1) = -3 + 15 - 2 = 10
C13 = (-1)*5 + (-3) *2 + 2*1 = -5 - 6 +2 = -9
C21 = 2*3 + 5*2 + (-1)*(-4) = 6 +10 + 4 = 20
C22 = 2*3 + 5*(-5) + (-1)*(-1) = 6 - 25 + 1 = -18
C23 = 2*5 + 5 *2+ (-1)*1 = 10 + 10 -1 = 19
C31 = (-4)*3 + (- 5)*2 + (-4)*(-4) = -12 - 10 +16 = -6
C32 = (-4)*(3) + (- 5)*(-5) + (-4)*(-1) = -12 + 25 + 4 = 17
C33 = (-4)*5 + (- 5)*2 + (-4)*1 = -20 - 10 - 4 = -34