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marta [7]
3 years ago
9

Can u help me plz thanks

Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0
1. x = -4 ; f(x) = -(-4) = 4
2. x = -3 ; f(x) = 2(-3) + 1 = -5
3. x = 0 ; f(x) = 2(0) + 1 = 1
4. x = 2 ; f(x) = 2 + 3 = 5
5. x = 5 ; f(x) = 5 + 3 = 8
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Change the fraction into a decimal
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Translate the word phrase into a variable expression.the quotient of a number and 3 is decreased by 1.
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 You are dividing a number (x) by three and then subtracting 1 like this.  (x/3)-1
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Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
1. La suma de dos números es 115. El número mayor es dos veces más 22 unidades que el otro. Hallar
Lerok [7]

De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.

----------------

  • En el sistema de ecuaciones, tiene-se que los números son x e y.
  • Suma de 115, o sea, x + y = 115
  • <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea, x = 2y + 22

----------------

Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>

x + y = 115

2y + 22 + y = 115

3y = 93

y = \frac{93}{3}

y = 31

----------------

El número mayor es dado en <u>función de el menor</u>, o sea:

x = 2y + 22 = 2(31) + 22 = 62 + 22 = 84

Los números son 31 y 84.

Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096

6 0
2 years ago
0.336 divided by 0.2​
Lilit [14]
1.68 I hope it helps!
7 0
3 years ago
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