Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
Answer: 2145 ²
Step-by-step explanation:
Answer with Step-by-step explanation:
We are given that height of projectile after t seconds is given by

a.h(t)=144 ft






t-3=0
t=3
After 3 s, the height of the project will be 144 feet in the air.
b.h(t)=0




At t=0, the initial position of projectile
At t=6 s , the projectile will hit the ground.
Step 1- Set up the equation.
Step 2- Divide the first digit.
Step 3- Divide the first two digits.
Step 4- Enter the first digit of the quotient.