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if there are 13 cookies birthday party is there any way to divide them equally amongst a group of friends so that each has a who

Neporo4naja [7]

Answer:

yes but it depends on how many friends are in the friend group

8 0

3 years ago

SurveyMonkey is a popular website for hosting online surveys and from time to time they will also create surveys based on a subj

krek1111 [17]

Answer:

So we use the t-distribution to compute a confidence interval for the average age of people using online dating services

Step-by-step explanation:

Confidence interval for a mean.

We have to decide between the t-distribution and the z-distribution.

T-distribution: We use the sample standard deviation.

Z-distribution: We use the population standard deviation.

In this problem:

The average age of those that were using online dating services was 35 years old with a sample standard deviation of 12 years.

So we use the t-distribution to compute a confidence interval for the average age of people using online dating services

6 0

3 years ago

I dont know!!!!!!!!!!!!!!!!!!!!!!!

djyliett [7]

Answer:

9in2

Step-by-step explanation:

the 2 is an expononent.

3 0

3 years ago

Help please!!!!!!!!!

In-s [12.5K]

ANSWER

24

EXPLANATION

For a matrix A of order n×n, the cofactor $C_{ij}$ of element $a_{ij}$ is defined to be

$C_{ij} = (-1)^{i+j} M_{ij}$

$M_{ij}$ is the minor of element $a_{ij}$ equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.

Here, we have

$C_{11} = (-1)^{1+1} M_{11} = M_{11}$

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \end{aligned}$

Since the determinant of a 2×2 matrix is

$\det\left( \begin{bmatrix} a & b \\ c& d \end{bmatrix} \right) = ad-bc$

it follows that

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}$

so $C_{11} = M_{11} = 24$

4 0

3 years ago

Korey kept track of the number of miles he ran each week for five weeks. The median number of miles he ran during the five weeks

shepuryov [24]

Answer:

the correct answer would be A. the mean is when you add up all of them and divide it by how many numbers there are which in this case is 5. and the median is the number in the middle, in this case 20, therefore when you add up all numbers in A ,you get 105 and you divide it by 5 which gives you 21. :))

6 0

3 years ago