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makkiz [27]
2 years ago
13

What does five times the number of books in the library

Mathematics
1 answer:
777dan777 [17]2 years ago
6 0
Well say for instence the variable was 75? It would be 5 x 75 which equals 375
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PLSS HELP
Dmitry [639]

Answer:

$8,000

Step-by-step explanation:

Let the store earned $x in December.

Therefore,

Money spent to buy new inventory =\frac{1}{4} x

Remaining money = x - \frac{1}{4} x =\frac{3}{4} x

Money used to pay bills =\frac{1}{2} \times \frac{3}{4} x=\frac{3}{8} x

Money still left over = $3,000

Total money earned in December = \frac{1}{4} x+ \frac{3}{8} x+3,000

\therefore x= \frac{1}{4} x+ \frac{3}{8} x+3,000

\therefore x= \frac{2}{8} x+ \frac{3}{8} x+3,000

\therefore x= \frac{5}{8} x+ 3,000

\therefore x- \frac{5}{8} x=3,000

\therefore \frac{8x-5x}{8} =3,000

\therefore \frac{3x}{8} =3,000

\therefore x =3,000\times \frac {8}{3}

\therefore x =1,000\times 8

\therefore x =\$8,000

Thus, total money earned in December is $8,000.

3 0
2 years ago
What is the inverse of the function f(x) = 2x – 10
BartSMP [9]

Answer:

y = 1/2x +5

Step-by-step explanation:

change f(x) to y

y = 2x - 10

then switch x and y

x = 2y - 10

then solve for y

add 10 to both sides and divide both sides by 2

6 0
2 years ago
Read 2 more answers
Can you guys help me? :-(
VMariaS [17]

Answer:

\frac{9}{10}

Step-by-step explanation:

Find the LCD because like last time, you cannot add or subtract fractions with different denominators.

LCD = 10

Since the second fractions stayed at the same denominator, you will only have to multiply the first fraction.

\frac{2 * 2}{5 * 2}

\frac{4}{10}

\frac{4 + 5}{10}

= \frac{9}{10}

5 0
3 years ago
Read 2 more answers
If a car is traveling east when it passes the camera, will its position be positive or negative 60 seconds after it passes the c
dexar [7]

Step-by-step explanation:

I can only answer part 2 of your question, "If we multiply two positive numbers, is the result positive or negative?". if you multiply 2 positive numbers your answer would be positive.

7 0
3 years ago
a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco
lina2011 [118]
\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)

The probability of drawing a red marble on the first attempt is

\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event R_1). So

\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27

And so

\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}
4 0
3 years ago
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