Answer:
Susan has suggested a correct method to calculate the amount of money
Step-by-step explanation:
Here we must check what each person is calculating. First, we consider Susan's method. She has suggested that we multiply the cost per soda, that is dollars/soda by the number of sodas required, we get the total cost.
Assuming that 18 sodas are required and each costs $0.20, the total cost according to Susan is $3.60.
John suggests we divide the cost of a 12 pack of soda by the number of sodas required. Considering a 12 pack of soda costs $12 and the same amount of sodas, 18, are required, we get that each soda costs $0.66.
Looking at these answers, we see that Susan has suggested a correct method to calculate the amount of money needed to buy a number of sodas. John has suggested the amount each person would have to contribute if everyone at the party was trying to buy a 12-pack of soda; regardless of whether more or less than a 12-pack is required.
Answer:
See below ~
Step-by-step explanation:
<u>Things to Find</u>
- Volume of Toy
- Difference of Volumes in Cube and Toy
- Total Surface of Toy
<u>Volume of Toy</u>
- Volume of Hemisphere + Volume (Cone)
- 2/3πr³ + 1/3πr²h
- 1/3πr² (2r + h)
- 1/3 x 3.14 x 16 (8 + 4)
- 1/3 x 50.24 x 12
- 50.24 x 4
- <u>200.96 cm³</u>
<u></u>
<u>Volume of Circumscribing Cube</u>
- Edge length is same as diameter
- V = (8)³
- V = 512 cm³
<u>Difference in Volume</u>
- 512 - 200.96
- <u>311.04 cm³</u>
<u></u>
<u>Slant height of cone</u>
- l² = 4² + 4²
- l² = 32
- l = 4√2 cm = 5.6 cm
<u />
<u>Surface Area of Toy</u>
- CSA (hemisphere) + CSA (Cone)
- 2πr² + πrl
- πr (2r + l)
- 3.14 x 4 (8 + 5.6)
- 12.56 x 13.6
- <u>170.8 cm²</u>
The answer would be:
6x - 7
I hope this helped you,
Have a great day
Answer:
125,000
Step-by-step explanation:
Take the Japanese yen and divide by 12
1,500,000 divided by 12 = 125,000
A segment bisector is a segment, ray, line, or plane that intersects a given segment at its midpoint.
For example, in the diagram shown, line SQ bisects segment PR because line SQ intersects segment PR at its midpoint which is Q.
