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SCORPION-xisa [38]
3 years ago
10

How do you reduce 135/50

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

27 / 10 or 2.7

Step-by-step explanation:

135/50

To reduce it, do as following:

Divide it by 5, we got:

135/5 / 50/5

= 27 / 10 or 2.7

Hope this helped :3

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Which expression can be used to fine the slope of a line containing the points (-3,2) and (7,-1)
Charra [1.4K]

Hello there! you can use the expression \frac{ y_{1}-y_{2}}{x_{1}-x_{2} }!

To find slope, subtract the y values over the x values.

In this case:

2 - - 1 / - 3 - 7

3 / -10

So, -3/10 would be the slope of these points.

Hope this helps, have a great day!

7 0
3 years ago
100 points what is 6x2
Ray Of Light [21]

Answer: 12

Step-by-step explanation:

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1 year ago
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Joy drank 2 3 liter of water Monday before going jogging. She drank 5 7 liter of water after her jog. How much water did Joy dri
Alexxandr [17]

Answer: 1 ⁸/₂₁ litres

Step-by-step explanation:

First find a common multiple to enable you add them up:

= 21

21 will be the denominator.

Multiply each numerator by the number you get when you divide 21 by the denominator.

= 21/3 = 7

= 7 * 2 = 14

= 21/7 = 3

= 3 * 5

= 15

= \frac{14 + 15}{21} \\\\= \frac{29}{21}

= 1\frac{8}{21} litres

8 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }

The critical value of <em>t</em> is:

\alpha /2=0.05/2=0.025

degrees of freedom =n_{1}+n_{2}-2=200+200-2=398

t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96

Compute the 95% confidence interval for the difference between two mean as follows:

CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0
3 years ago
Which of these numbers is greater than 2.25 but less than 1? Is it 1 or 1.5 or 0 or 2.5
Sloan [31]

Answer:

the answer is 1.5 because converting them into their fractional form indeed informs u that 1.5 is thus greater than 2.25 BT lesser than 1

5 0
3 years ago
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