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3 years ago

How do you reduce 135/50

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

Answer:

27 / 10 or 2.7

Step-by-step explanation:

135/50

To reduce it, do as following:

Divide it by 5, we got:

135/5 / 50/5

= 27 / 10 or 2.7

Hope this helped :3

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CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars

velikii [3]

Answer:

P(939.6 < X < 972.5) = 0.6469

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars.

This means that $\mu = 965, \sigma = 113$

Sample of 57:

This means that $n = 57, s = \frac{113}{\sqrt{57}} = 14.97$

Find the probability that a single randomly selected policy has a mean value between 939.6 and 972.5 dollars.

This is the pvalue of Z when X = 972.5 subtracted by the pvalue of Z when X = 939.6. So

X = 972.5

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{972.5 - 965}{14.97}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

X = 939.6

$Z = \frac{X - \mu}{s}$

$Z = \frac{939.6 - 965}{14.97}$

$Z = -1.7$

$Z = -1.7$ has a pvalue of 0.0446

0.6915 - 0.0446 = 0.6469

P(939.6 < X < 972.5) = 0.6469

3 0

2 years ago

Please help these problems are hard

Pachacha [2.7K]

Answer:

2/5

Step-by-step explanation:

For the denominator you are looking for the total number of options, and in this case it is 10. Then for the numerator you are looking for what the question is asking for, in this case, it is looking for letters n to q. n, o, p and q are what you are looking for. With this information you will get 4/10 and simplified, 2/5

6 0

3 years ago

A student answered 86 problems on a test correctly and received a grade of 98%. How many problems were on the test, if all the p

balu736 [363]

Answer:

88 problems

Step-by-step explanation:

Set this problem up as fractions

86/x = 98/100

Cross multiply

86 × 100 = x × 98

8600 = 98x

Divide both sides by 98

87.75... = x

Round to nearest whole number

87.75 rounds up to 88

88 problems

7 0

3 years ago

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

sp2606 [1]

Answer:

(A) The odds that the taxpayer will be audited is approximately 0.015.

(B) The odds against these taxpayer being audited is approximately 65.67.

Step-by-step explanation:

The complete question is:

Suppose the probability of an IRS audit is 1.5 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more.

A. What are the odds that the taxpayer will be audited?

B. What are the odds against such tax payer being audited?

Solution:

The proportion of U.S. taxpayers who were audited is:

P (A) = 0.015

Then the proportion of U.S. taxpayers who were not audited will be:

P (A') = 1 - P (A)

= 1 - 0.015

= 0.985

(A)

Compute the odds that the taxpayer will be audited as follows:

$\text{Odds of being Audited}=\frac{P(A)}{P(A')}$

$=\frac{0.015}{0.985}\\\\=\frac{3}{197}\\\\=0.015228\\\\\approx 0.015$

Thus, the odds that the taxpayer will be audited is approximately 0.015.

(B)

Compute the odds against these taxpayer being audited as follows:

$\text{Odds against Audited}=\frac{P(A')}{P(A)}$

$=\frac{0.985}{0.015}\\\\=\frac{3}{197}\\\\=65.666667\\\\\approx 65.67$

Thus, the odds against these taxpayer being audited is approximately 65.67.

8 0

3 years ago

Find the slope of each line

melamori03 [73]

Answer:

0, -2/3

Step-by-step explanation:

5 0

3 years ago