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iVinArrow [24]
3 years ago
13

Someone explain I don’t get it

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

neither do I'm stuck on that one

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How many solutions do consistent dependent lines have
user100 [1]
A consistent system has at least 1 solution, it could have more.

a consistent system that has exactly 1 solution, is an independent system.

a consistent system that has infinitely many solutions, namely, both equations are really the same equation in disguise, is a dependent system.

5 0
3 years ago
WILL GIVE BRAINIEST TO THE PERSON THAT ANSWERS ALL THREE QUESTIONS ASAP!
Radda [10]

Answer:

1. Your answer would be C) 2√3-5√2.

2. Your answer would be -39.7i.

3. Your answer would be -1.

Step-by-step explanation:

8 0
3 years ago
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HELP ME! I hate math + I’m probably going to get it wrong
marin [14]
Again, simplify.
4x - 5.
x - 1.25. Hope it helps!
4 0
4 years ago
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What value of p gives one real solution to x^2=p.
yawa3891 [41]
The answer would be zero. 0^2=0 and the square root of 0=0
3 0
3 years ago
Can you express 14 17 ?23 as a linear combination of V?<br><br> V= (2 1 -1), (1 -1 2), (4 5 -7)
KATRIN_1 [288]

Answer:

No ,we cannot express 14,17,23 as a linear combination of V

Step-by-step explanation:

Here 14,17,23 can be written as linear combination of V if we have a,b and c all non zero such that

(14,17,23) = a(2,1,-1)+b(1,-1,2)+c(4,5,-7)

(14,17,23) = (2a,a,-a)+(b,-b,2b)+(4c,5c,-7c)   [ scalar multiplication ]

(14,17,23)= (2a+b+4c,a-b+5c,-a+2b-7c)    [ vector addition ]

2a+b+4c = 14               equation 1

a-b+5c= 17                  equation 2

-a+2b-7c =23             equation 3

Here we  have three simultaneous equations

Since equation 2 and 3 has sign of a is opposite  with coefficient 1,adding both equations,we get

b-2c = 40

multiplying equation equation 3 by 2 and adding it to equation 1 in order to eliminate the term a

2a+b+4c=14

-2a+4b-14c=46

adding 5b-10c = 60

           divide it both sides by 5 ,we get

              b -2c = 12

here we see that  left side of two equations same but right side is not same

therefore solution doesnt exist .

Moreover given set of Vectors in V are not linear independent

since their determinant is zero

in order to write linear combination ,we need to have linearly independent vectors

there exist not values of a  ,and c

therefore we cannot express 14,17,23 as linear combination of V

8 0
3 years ago
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