I need help with 1-4

How to do it and the answer

Anastasy [175]

Answer:

Answer is :- Each pork chop weight is 4.8 ounces.

Step-by-step explanation:

Given,

A 3 pound pork can be cut into 10 pork chops of equal weight.

Weight of one pork chop = 3/10 pounds

or Weight of one pork chop = 0.3 pound

We can convert 0.3 pounds into ounces

Since 1 pound = 16 ounces

Then, 0.3 pound = 16 * 0.3 ounces

or 0.3 pound = 4.8 ounces

Hence each pork chop weight is 4.8 ounces.

8 0

2 years ago

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0

2 years ago

Solve for x rounded to the nearest hundredth: 10 - 3x = 5

igomit [66]

Answer:

x = 5/3

Step-by-step explanation:

You ALWAYS want your term to be by itself!! So what you need to do is move your constant away from it.

Step 1: Adjust as needed, subtract 10 from both sides of your equation. It should end up like this.

-3x = 5 - 10

Step 2: Solve as needed before continuing equation.

-3x = -5

Step 3: Now you need to get your term by itself. You should divide -3 on both sides of your equation so you should get something like this.

x = -5 / -3

Step 4: You're basically done now! Just simplify! NEGATIVES CROSS EACH OTHER OUT!!!

x = 5/3 OR 1.6

KEY:

Negative and Negative = Positive

Negative and Positive = Negative

Positive and Positive = Positive

4 0

3 years ago

In the equation y = -2x, if x is doubled, what happens to y? stays the same doubles quadruples unknown, since a value for x is n

OLEGan [10]

In an equation like that, y would double into 2y. But just keep in mind that what happens to one side must happen to another.

3 0

3 years ago

A taxi driver provides service in two zones of a city. Fares picked up in zone A will have destinations in zone A with a probabi

sammy [17]

Answer:

The taxi driver's average profit per trip is 4.4.

Step-by-step explanation:

Probability of fares picked up in zone A with destinations in zone A = 0.6

Probability of fares picked up in zone A with destinations in zone B = 0.4

Probability of fares picked up in zone B with destinations in zone A = 0.3

Probability of fares picked up in zone B with destinations in zone B = 0.7

The driver's expected profit for a trip entirely in zone A = 6

The driver's expected profit for a trip entirely in zone B = 8

The driver's expected profit for a trip involving both zones is 12

The taxi driver's average profit per trip:

zone A with destinations in zone A = 0.6 * 6 = 3.6

zone A with destinations in zone B = 0.4 * 12 = 4.8

zone B with destinations in zone A = 0.3 * 12 = 3.6

zone B with destinations in zone B = 0.7 * 8 = 5.6

Total profit expected for 4 trips = 17.6

Average profit per trip = 4.4 (17.6/4)

7 0

2 years ago