Answer:
JUST ADD 3$
Step-by-step explanation:
Let
denote the
th partial sum of the series, i.e.
Then
and subtracting from
we get
As
, the exponential term vanishes, leaving us with
and so
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
First subtract 3 from both sides of the equal sign.
9s + 3 = 57
- 3 -3
9s = 54
Then divide both sides by 9.
9s = 54
/9 /9
s = 6
You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6 + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)
Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations.
