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gayaneshka [121]
2 years ago
9

What is the least common multiple of 3, 17, and 51?

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
7 0

Answer:

The answer is B

Step-by-step explanation:

Oxana [17]2 years ago
3 0
Answer is B!!!!!!!!!!!!!!!!
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What is the product of 3.4 × 10−14 and 1.8 × 10^28?
DENIUS [597]
None of the answer matches the correct ans
(3.4×10-14)(1.8×10^28)
20(1.8×10^28)
3.6×10^29
8 0
3 years ago
An analyst from an energy research institute in California wishes to precisely estimate a 99% confidence interval of the average
Lena [83]

Answer:

190

Step-by-step explanation:

Data provided in the question:

Confidence level = 99%

Therefore,

α = 1% = 0.01

[ from standard normal table ]

z-value for z_{\frac{\alpha}{2}}= z_{\frac{0.01}{2}}= = 2.58

Margin of error, E = $0.06

Standard deviation, σ = $0.32

Now,

n = (\frac{z_{0.005}\sigma}{E})^2

Here,

n is the sample size (or the minimum number of gas stations  )

on substituting the respective values, we get

= (\frac{z_{0.005}\sigma}{E})^2

= (\frac{2.58\times0.32}{0.06})^2

= 13.76²

= 189.3376 ≈ 190

Hence,

minimum number of gas stations that she should include in her sample is 190

5 0
3 years ago
If you guys want I’ll make it 80 points + BRAINLIEST if you help me with my previous question just please please please let me k
lesya [120]

sure dude whats the question?


8 0
3 years ago
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
3 years ago
Imagine that the rectangle is rotated counterclockwise. Make a conjecture as to which properties of a figure stay the same after
bazaltina [42]
Angles, length, shape
8 0
3 years ago
Read 2 more answers
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