Let t and s represent the masses of 20% and 60% alloys respectively.
t+s=80, s=80-t
(0.2t+0.6s)/80=0.52 multiply both sides by 80
0.2t+0.6s=41.6, now using s=80-t in this equation gives us:
0.2t+0.6(80-t)=41.6 perform indicated multiplication on left side
0.2t+48-0.6t=41.6 combine like terms on left side
-0.4t+48=41.6 subtract 48 from both sides
-0.4t=-6.4 divide both sides by -0.4
t=16, since s=80-t
s=64
So 16kg of 20% alloy is mixed with 64kg of 60% allow to make 80kg of a 52% alloy.
(3x+7) / (x+5). ....................
Step-by-step explanation:
(4sin0 × 4sin0) +(4sin0 × -3cos0)+ (3cos0×4sin0) +(3cos0 × -3cos0)=
16 sin²0 - 12 sin0cos0 + 12 sin0cos0 -
9cos²0
= 16sin²0 - 9 cos²0
Answer:
If two lines intersect, then there is one plane
that contain(s) them
Step-by-step explanation:
According to the plane-line postulate, if two points lie in a plane, the line containing them lies on the plane.According to the line intersecting theorem, if two lines intersect, then exactly one plane contains both lines.This should be the line-intersecting theorem.
You answer is B
-10r=-115+6