
1. Find the percent markup.
Markup ($) = percent markup (%) x original cost ($)
A computer store buys a laptop for $635 directly from the manufacturer (Dell). The markup is $570. What is the percent markup on the computer?
The percent markup is: <u> </u><u>90</u><u> </u>%

FORMULA: Percent of Markup = Markup/Cost x 100
- = $570/$635 x 100
- = 0.90 x 100
- = 90%
Answer:
Step-by-step explanation:
8x^2 - 8x + 2 - 5 + x.....combine like terms
8x^2 - 7x - 3 <=== g = 7 and h = 3
Answer: (23.53, 25.47)
Step-by-step explanation:
The confidence interval for population mean(when population standard deviation is unknown) is given by :-

, where
= sample mean
n = sample size.
s = sample standard deviation.
t* = Critical value.
Given :
s= 4.4
Confidence level = 90% =0.090
Significance level = 
Sample size : n= 58
Degree of freedom : df= n-1= 57
Using t-distribution table , the critical value :

Then, the confidence interval will be :-



Hence, a 90% confidence interval for the population mean = (23.53, 25.47)
1. Li will not have enough apples. This is because 9 apples that each weigh approximately 150 grams would weigh a total of 1.35kg.
2. The caterpillar weighs 65.2 grams.
Hope this helps!
6(2 - 7v) - 4(-6v + 7)
multiply the first bracket by 6
(6)(2)=-12
(6)(-7v)=-42v
multiply the second bracket by -4
(-4)(-6v)=-24v
(-4)(7)=-28
12-42v+24v-28
-16-18v
Answer:
-16-18v or -18v-16