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Elenna [48]
4 years ago
9

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German. What is the la

rgest possible number of students in that class?
Mathematics
1 answer:
Marina CMI [18]4 years ago
6 0

Solution:

we are given that

In a class, every student knows French or German (or both).

15 students know French, and 17 students know German.

Suppose there are x student who knows both French and German.

Then Total number of student in the class will be (15+17-x)=32-x

But to guess the largest possible number of student in the class we can assume x=0

Hence the largest Possible number of Student in the class=32

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densk [106]

Answer:

x = (-9)/5

Step-by-step explanation:

Solve for x:

(-2 x)/9 = 2/5

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (-2 x)/9 = 2/5 by -9/2:

(-9 (-2) x)/(2×9) = (-9)/2×2/5

Hint: | Express (-9)/2×(-2)/9 as a single fraction.

(-9)/2×(-2)/9 = (-9 (-2))/(2×9):

(-9 (-2))/(2×9) x = (-9)/2×2/5

Hint: | Express (-9)/2×2/5 as a single fraction.

(-9)/2×2/5 = (-9×2)/(2×5):

(-9 (-2) x)/(2×9) = (-9×2)/(2×5)

Hint: | In (-9 (-2) x)/(2×9), divide -9 in the numerator by 9 in the denominator.

(-9)/9 = (9 (-1))/9 = -1:

(-2-1 x)/2 = (-9×2)/(2×5)

Hint: | In (-(-2) x)/2, divide -2 in the numerator by 2 in the denominator.

(-2)/2 = (2 (-1))/2 = -1:

--1 x = (-9×2)/(2×5)

Hint: | Multiply all instances of -1 in -(-x).

(-1)^2 = 1:

x = (-9×2)/(2×5)

Hint: | Cancel common terms in the numerator and denominator of (-9×2)/(2×5).

(-9×2)/(2×5) = 2/2×(-9)/5 = (-9)/5:

Answer: x = (-9)/5

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Answer:

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Step-by-step explanation:

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