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Bumek [7]
3 years ago
14

I NEED SOME HELP ITS DUE TOMORROW

Mathematics
1 answer:
oee [108]3 years ago
8 0
348 fluid ounces = 2/3 of the water.
So, 1/3 of the jar would be = 348 ÷ 2 = 174.
Three-thirds of the jar = (1/3) × 3 = 174 × 3 = <em>522</em><em></em>.

- The jar can hold 522 fluid ounces of water.

<em>I hope this helps! If it did, please mark me BRAINLIEST!!! (So that others can know my answer was the right answer, if they need the right answer)</em>
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What should a size of a sample be in order to have a margin of error of 4% for a 90% confidence level from a population with a s
vagabundo [1.1K]

Answer:

We need a sample size of 2,071,800 or higher.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

We need a sample size of n or higher, when M = 0.04, \sigma = 35. So

M = z*\frac{\sigma}{\sqrt{n}}

0.04 = 1.645*\frac{35}{\sqrt{n}}

0.04\sqrt{n} = 1.645*35

0.04\sqrt{n} = 57.575

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\sqrt{n}^{2} = (1439.375)^{2}

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