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dezoksy [38]
3 years ago
11

Does an uppercase h have point symmetry?

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0
Yes. Point symmetry is effectively where an object is "the same upside down", or where every point has an identical counterpart the same distance from the point in the opposite direction. H can be flipped and remain symmetrical 
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Geometry question! Help!
Karolina [17]

Answer: 2\sqrt{2}

Step-by-step explanation:

The inradius is given by the area of the triangle divided by the semiperimeter.

The semiperimeter is \frac{12+12+8}{2}=16.

Thus, by Heron's formula, the area is \sqrt{16(16-12)(16-12)(16-8)}=32\sqrt{2}.

Therefore, the radius is \frac{32\sqrt{2}}{16}=2\sqrt{2}}

8 0
2 years ago
How many of the 200 total high school students would you expect to be less than68 inches tall?
Vika [28.1K]
I think the answer is A. 40.
7 0
4 years ago
the height of a tree was 8 feet. after a year, tree's height increased by 25%. use a bar diagram to find the new height of the t
marysya [2.9K]
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5 0
4 years ago
Product is a 12 ounce bottle of generic mouthwash that sells $4.39 product B is a 24 ounce bottle of mouthwash that cost $2.79 w
Anna35 [415]
Hi there,
To compare we can look at the amount of (ounces)
A: 12         B:24
so as it appears B wins this part
Now price 
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A is relatively expensive than B
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5 0
3 years ago
Cos(−θ)=√3/3, sinθ<0
Delicious77 [7]

Answer:

\sin\theta=-\frac{\sqrt{6}}{3}


Step-by-step explanation:

The given trigonometric equation is \cos(-\theta)=\frac{\sqrt{3} }{3}.

We can either use the Pythagorean identity or the right angle triangle  to solve for \sin\theta.

According to the Pythagorean identity,

\cos^2\theta+\sin^2\theta=1


Recall that, the cosine function is an even function, therefore

\cos(-\theta)=\cos(\theta)


\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}.

We substitute this value in to the above Pythagorean identity to get;


(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1


\Rightarrow \frac{3}{9}+\sin^2\theta=1


\Rightarrow \sin^2\theta=1-\frac{3}{9}


\Rightarrow \sin^2\theta=\frac{6}{9}


\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}


\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}


But we were given that,

\sin\theta\:, so we choose the negative value.

\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}


The correct answer is B







7 0
4 years ago
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