Answer:1/6
Step-by-step explanation: So you toss it 3 times(1/3) and you have 50% chance(1/2) of choosing heads or tails... so,
1/3 x 1/2 = 1/6
Ummmmmmm yeah..what is this
Answer:
A,C and E
Step-by-step explanation:
because Im the only one thats answered your question so you don't exactly have anything else to go off of
Given:
In a triangle, length of one side is 8 inches and length of another side is 12 inches, and an angle is a right angle.
To find:
The length of the missing side.
Solution:
In a right angle triangle,

Suppose the measures of sides adjacent to the right angle are 8 inches and 12 inches.
Substituting Perpendicular = 8 inches and Base = 12 inches, we get



Taking square root on both sides, we get



The length of the missing side is 14.4 inches. Therefore, the correct option is D.
As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).