All categories

3 years ago

Is this right and if it's not could you please tell me the answer

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

3x+ 5 = 6 . Correct.

Step-by-step explanation:

Let x = the number.

The number tripled: 3x

Tripled and increased by : 3x + 5

Equals 6: 3x+ 5 = 6

Correct.

You might be interested in

Ruiz needs to buy a countertop for a kitchen. He calculated the area to be 16 square feet. The actual area is 15.4 square feet.

igomit [66]

Percentage error $=\frac{error}{actual measurement} \times 100$
Here error = 16 - 15.4 = 0.6
Therefore, percentage error $=\frac{0.6}{15.4} \times 100=0.039 \times 100$
=3.9%

3 0

3 years ago

Read 2 more answers

What is true about the solution of x^2 / 2x - 6 = 9 / 6x - 18

DanielleElmas [232]

$\text{The domain}\\2x-6\neq0\ \wedge\ 6x-18\neq0\to x\neq3\\\\\dfrac{x^2}{2x-6}=\dfrac{9}{6x-18}\\\\\dfrac{x^2}{2(x-3)}=\dfrac{9}{6(x-3)}\ \ \ |\cdot6\\\\\dfrac{3x^2}{x-3}=\dfrac{9}{x-3}\iff3x^2=9\ \ \ |:3\\\\x^2=3\to x=\pm\sqrt3$

4 0

3 years ago

Read 2 more answers

Emma has a spool of ribbon that has 5 meters on it. She cut a length of ribbon that was 0.9 meters long. Then she cut another le

Inessa05 [86]

Answer:

2.6 meters.

Step-by-step explanation:

5-0.9 is 4.1, minus 1.5 is 2.1.

7 0

3 years ago

Read 2 more answers

Rewrite the quadratic function in vertex form.<br> Y=3x^2-12x+4

chubhunter [2.5K]

Answer:

$\large\boxed{y=3(x-2)^2-8}$

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

$f(x)=a(x-h)^2+k$

(h, k) - vertex

$h=\dfrac{-b}{2a},\ k=f(h)$

We have the equation:

$y=3x^2-12x+4\\\\a=3,\ b=-12,\ c=4$

Substitute:

$h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8$

Finally:

$y=3(x-2)^2+(-8)=3(x-2)^2-8$

4 0

3 years ago

A small combination lock on a suitcase has 55 wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar

den301095 [7]

Suppose $a_n$ is the number of possible combinations for a suitcase with a lock consisting of $n$ wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for $n+1$ wheels, or $a_{n+1}$ is given recursively by the formula

$a_{n+1}=9a_n$

starting with $a_1=10$ (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

$a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n$

This means a lock with 55 wheels will have

$a_{55}=10\times9^{54}$

possible combinations (a number with 53 digits).

7 0

3 years ago