Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
Answer:
4 hours
Step-by-step explanation:
Alright, so Steve has $50 in his pocket. He wants to rent a bike for the maximum amount of time possible with his money. It costs him $12 per hour to rent a bike.
To solve this problem use simple arithmetic:
($50/$12=4.16)
So Steve is able to rent the bike for 4.16 hours, but we aren't done yet. Steve cannot purchase 16% of an hour, he can only buy FULL hours, so with his $50 , the maximum amount of time he can buy is 4 hours!
Let me know if you need any further explanations :)
<u>Answer:</u>
The amount lost over the 3 years s 2567.25£
<u>Explanation:</u>
where F = final value after n years
I = initial value of the car in 2017 = £18000 (given)
Since the value is depreciated 5% every year for 3 years,
r = percentage rate of depreciation = 5% (given)
n = 3 years
Substituting these values in formula, we get
=
= 15432.75£ which is the value of the car after 3 years
Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.
Answer:
C. G
Step-by-step explanation:
