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The ball’s speed and direction at the lowest point of trajectory are; 3.1 m/s and swing to the same angle on the other side
<h3>What is the speed at the lowest point?</h3>
We will assume that all of the motion will transfer to Kinetic Energy at the lowest point. Now, the difference in height will be;
Δh = (130 – 130*cos °5) = 0.49 cm
The change in PE is;
ΔP.E = mgΔh
ΔP.E = 9.8m/s² × 0.75kg × 0.049 m
ΔP.E = 0.36015 J
Formula for kinetic energy is;
K.E = ¹/₂*m*v²
From conservation of energy;
K.E = P.E
Thus;
¹/₂* 0.075 * v² = 0.36015
v = √[(0.36015 * 2)/0.075]
v = 3.1 m/s
Thus, the pendulum will swing to the same angle on the other side.
Read more about Speed of Pendulum at; brainly.com/question/17054952
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