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Katyanochek1 [597]
3 years ago
13

Anasenasatmananandamam8cmbcm5cm8 cm​

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

???

Step-by-step explanation:

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Mr. John Doe was fighting out his federal income tax. His income was $26,800, but he was able to subtract $5,500in deductions. H
Ber [7]

Answer:

             

Step-by-step explanation:

                                           

7 0
3 years ago
I) Construct a triangle PQR such that |PQ|=8cm,{RPQ=90°{PQR=30°.Measure |RQ|​
scoray [572]

Answer:

6.93 cm

Step-by-step explanation:

You have a right triangle (90°), so you do as follow:

If I understand correctly, you are looking for the hypotenuse so

cos(30) = \frac{PQ}{QR} = \frac{8 cm}{QR}

That is equal to QR = cos(30)*8 cm = 6.928 cm

5 0
3 years ago
What is 1/4 plus 1/3, will give brainliest and thank you and rate and give 15 points plz help
Slav-nsk [51]
First, you have to convert 1/4 and 1/3 to have the same denominator. 

So, 1/4 x 3 = 3/12. 1/3 x 4 = 4/12.

Now, you can add 3/12 + 4/12 = 7/12.
4 0
3 years ago
The variable Z is directly proportional to X. when X is 15, Z has the value of 45. what is the value of Z when X=23
IrinaVladis [17]
If\ Z\ is\ directly\ proportional\ to\ X\ then\ \frac{Z}{X}=const.\\------------------------\\X=15\ and\ Z=45\\\\X=23\ and\ Z=?\\\\\frac{Z}{23}=\frac{45}{15}\to\frac{Z}{23}=3\ \ \ \ |multiply\ both\ sides\ by\ 23\\\\\huge\boxed{Z=69}
8 0
4 years ago
Nu is designing a rectangular sandbox.The bottomm is 16 square feet.Which dimensions require the least amount of materail for th
zzz [600]

Given Information:  

Area of rectangle = 16 square feet

Required Information:  

Least amount of material = ?

Answer:

x = 4 ft and y = 4 ft

Step-by-step explanation:

We know that a rectangle has area = xy and perimeter = 2x + 2y

We want to use least amount of material to design the sandbox which means we want to minimize the perimeter which can be done by taking the derivative of perimeter and then setting it equal to 0.

So we have

xy = 16  

y = 16/x

p = 2x + 2y

put the value of y into the equation of perimeter

p = 2x + 2(16/x)

p = 2x + 32/x

Take derivative with respect to x

d/dt (2x + 32/x)

2 - 32/x²

set the derivative equal to zero to minimize the perimeter

2 - 32/x² = 0

32/x² = 2

x² = 32/2

x² = 16

x = \sqrt{16} = 4 ft

put the value of x into equation xy = 16

(4)y = 16

y = 16/4

y = 4 ft

So the dimensions are x = 4 ft and y = 4 ft in order to use least amount of material.

Verification:

xy = 16

4*4 = 16

16 = 16 (satisfied)

7 0
3 years ago
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