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Elza [17]
3 years ago
13

The only three regular polygons that tessellate are _____ equilateral triangles, squares, and regular hexagons. squares, regular

hexagons, and regular octagons. squares, regular pentagons, and regular hexagons. equilateral triangles, squares, and regular pentagons.
Mathematics
2 answers:
Bumek [7]3 years ago
5 0
<span>equilateral triangles, squares, and regular hexagons</span>
iVinArrow [24]3 years ago
3 0
<h2>Answer:</h2>

The equilateral triangles, squares, and regular hexagons tessellate.

Step-by-step explanation:

Tessellation means when a plane surface is covered with a single shape, without gaps or overlapping the shape.

If the shape is equal from all sides, it will fit together when it is repeated. This is the reason only regular polygons tessellate. When we translate or slide any regular polygon, the sides of both the original and translated shape will be equal.

This is the reason, equilateral triangles, squares, and regular hexagons tessellate.

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<em><u>Note: The complete question, along with the graph, is attached below.</u></em>

<em><u /></em>

Answer:

The value of a = 3

Step-by-step explanation:

Given the function

f\left(x\right)=a\left(b^x\right)

From the attached graph, it is clear that

at x = 0,

f\left(0\right)=a\left(b^0\right)

\:f\left(0\right)\:=\:a\:\times \:1         ∵ b^0=1

f\left(0\right)=a

Thus

When x = 0, the y-intercept will be:

f\left(0\right)=a

From the attached figure, it is clear that

at x = 0, the value of y = 3

so

putting y = 3 in the equation

f\left(0\right)=a

3 = a            ∵ f\left(0\right)=y=3

Therefore, the value of a = 3

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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