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makvit [3.9K]
3 years ago
12

Subtract 4 1/5 - 3/4

Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Change both fractions, so they have the same denomater

4 1/5= 4 4/20

3/4= 15/20

change the mixed number into an improper fraction

84/20Subtract 15 from 84

84-15=69

so you get 69/20

Hope this helped :)

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iogann1982 [59]

Answer:

The vertex of the function is at (1,-25)

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown  below. </em>

<em>Which statements about the function are true? Select two </em>

<em>options. </em>

<em>The vertex of the function is at (1,-25). </em>

<em>The vertex of the function is at (1,-24). </em>

<em>The graph is increasing only on the interval -4< x < 6. </em>

<em>The graph is positive only on one interval, where x <-4. </em>

<em>The graph is negative on the entire interval  </em>

My answer:

Given the factored form of the function:

f(x) = (x + 4)(x-6)

<=> f(x) = x^{2} - 2x -24

We will convert to vertex form

<=> f(x) = (x^{2} - 2x +1) - 25

<=> f(x) = (x-1)^{2} -25

=> the vertex of the function is: (1,-25)

We choose: a. The vertex of the function is at (1,-25)

Let analyse other possible answers:

<u>c. The graph is increasing only on the interval -4< x < 6.</u>

Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.

So the graph is increasing in the domain (1, +∞)

=> C is wrong

<u>d. The graph is positive only on one interval, where x <-4</u>

Wrong, The graph is positive only on one interval, where x > 6

<u>e. The graph is negative on the entire interval</u>

Wrong, The graph is negative only on one interval, where -4< x < 6.

7 0
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