Answer A
They have the same x-intercept but different end behavior as x approaches ∞ :)
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
Answer:
area of this circle: 490.6 inch²
Step-by-step explanation:
area of circle: π(radius)²
Here the diameter is given 25 inch, so the radius will be half: 25/2 → 12.5 in
using the formula:
3.14(12.5)²
490.625 inch²
490.6 inch²____rounded to nearest tenth.
Answer:68%
Step-by-step explanation:
find area of the circle=50.2
Find the are of the triangle=16
Then find ratio=16/50.2
Then reduce=8/25.1=32%
Then subtract= 100-32=68%
