If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
Answer:
We need at least 243 stores.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is:
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
For this problem, we have that:
![n = 70, p = \frac{62}{70} = 0.886](https://tex.z-dn.net/?f=n%20%3D%2070%2C%20p%20%3D%20%5Cfrac%7B62%7D%7B70%7D%20%3D%200.886)
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.
We need at least n stores.
n is found when M = 0.04. So
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}](https://tex.z-dn.net/?f=0.04%20%3D%201.96%5Csqrt%7B%5Cfrac%7B0.886%2A0.114%7D%7D%7Bn%7D%7D)
![0.04\sqrt{n} = 1.96\sqrt{0.886*0.114}](https://tex.z-dn.net/?f=0.04%5Csqrt%7Bn%7D%20%3D%201.96%5Csqrt%7B0.886%2A0.114%7D)
![\sqrt{n} = \frac{1.96\sqrt{0.886*0.114}}{0.04}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B1.96%5Csqrt%7B0.886%2A0.114%7D%7D%7B0.04%7D)
![(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.886*0.114}}{0.04})^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%28%5Cfrac%7B1.96%5Csqrt%7B0.886%2A0.114%7D%7D%7B0.04%7D%29%5E%7B2%7D)
![n = 242.5](https://tex.z-dn.net/?f=n%20%3D%20242.5)
Rounding up
We need at least 243 stores.
Answer: Odds in favor = Number of successes: Number of failures
Step-by-step explanation:
Example
A jewelry box contains 5 white pearl, 2 gold rings and 6 silver rings. What are the odds of drawing a white pearl from the jewelry box?
Number of successes = 5
Number of failures = 2 + 6 = 8
Numbers of ways to draw a white pearl: number of ways to draw another jewelry.
5:8
The odds are 5:8
Answer:
yes
Step-by-step explanation:
Answer:
Prime
Step-by-step explanation:
If we have a point on a pre-image, we can have it labelled as A(x,y)
Now, we can write this as the image
To write this as the image, we simply have to add a mark on the A
This mark is at the upper right
We have it as A’ (x,y)
The part added is called a prime