3 years ago

What is the sum of 6 thousand 5 hundred + 1 thousand 3 hundreds 4 tens

1 answer:

7 0

7840-group all the same denominations together like this: 6 thousand + 1 thousand is 7 thousand, 5 hundred +3 hundred is 8 hundred and 4 tens 4 times 10, means count by tens.

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2. Find the product (2x + 3)(3x - 2).

eimsori [14]

Answer:

6x² + 5x - 6

Step-by-step explanation:

Given

(2x + 3)(3x - 2)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(3x - 2) + 3(3x - 2) ← distribute both parenthesis

= 6x² - 4x + 9x - 6 ← collect like terms

= 6x² + 5x - 6

6 0

3 years ago

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Please help quickly!!

erastovalidia [21]

Answer:

Step-by-step explanation:

6 0

2 years ago

Help xd -(x+2) = 3(7x - 8)= 7(x+3)-5x Thank you!

HACTEHA [7]

Answer:

x=−5

x= 31/21 =1 10/21= 1.476190476

2x+21

hope this helps

3 0

3 years ago

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X^5 y^2 + x^2 y^5 Factor the expression completely.

Eduardwww [97]

Answer:

x^2 y^2(x+y)(x^2 - xy + y^2)

Step-by-step explanation:

x^2 y^2(x^3 + y^3)

(x+y)(x^2 - xy +y^2)

5 0

3 years ago

Find the distance between the points (0,-9) and(4,-6)

Len [333]

Answer:

d=5

Step-by-step explanation:

1. use the distance formula: d= $\sqrt{(x_{2} - x_{2} )^{2} +(y_{2} -y_{1} )^{2}$

2. plug in the points: d= $\sqrt{(0-4)^{2} +(-9+6)^{2}$

3. solve problem inside parentheses: d= $\sqrt{(-4)^{2} +(-3)^{2}$

4. square -4 and -3: d= $\sqrt{16+9$

5. add:d= $\sqrt{25$

6. find square root: d=5

8 0

3 years ago