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Mkey [24]
3 years ago
14

Given the terms a10 = 3 / 512 and a15 = 3 / 16384 of a geometric sequence, find the exact value of the term a30 of the sequence.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
The answer is \frac {3}{2^{29}}
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Explain why 3 : 2 and 9 : 8 are not equivalent ratios.
Wewaii [24]

Answer:

3:2 is equal to 12:8 and 12:8 is not 9:8

Step-by-step explanation:

Ratios are also fractions

3/2 is also 12/8

12/8 is not 9/8

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2 years ago
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What does the degree of a polynomial mean?
serg [7]
__Award Brainliest if helped!

Layman : The number of the largest power

Say  x^{2} +x+3 , Degree is 2 (X^2) 
and if x^{3} + x^{2} +x+3 , the Degree is 3. 

Technical : Largest exponent of variable. 
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3 years ago
Arun needs to buy 834 pounds of potting soil to fill a large flowerpot. Potting soil costs $0.60 per pound, including tax. What
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$500.4

Step-by-step explanation:

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3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
sladkih [1.3K]

Answer:

10.17 seconds

Step-by-step explanation:

substitute y=0 into the equation

0=-16x²+153x+98

then use the quadratic formula

a = -16

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5 0
2 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
3 years ago
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