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3 years ago

Given the terms a10 = 3 / 512 and a15 = 3 / 16384 of a geometric sequence, find the exact value of the term a30 of the sequence.

Mathematics

1 answer:

GenaCL600 [577]3 years ago

5 0

The answer is $\frac {3}{2^{29}}$

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You have a 20-ounce bottle of juice. You pour out 14 of the bottle to share with a friend. If you pour out 3 ounces for yourself

jeyben [28]

20-14=6 6-3=3 3/20 is the answer for the fraction of ounces left

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3 years ago

find the measure of the angle of the radius of the circle is 4 inches and the length of the arc is 8 pi.

NeTakaya

Since the angle is in radians, then s = rθ.

$\bf \textit{arc's length}\\\\
s=r\theta \quad 
\begin{cases}
r=4\\
s=8\pi 
\end{cases}\implies 8\pi =4\theta \implies \cfrac{8\pi }{4}=\theta \implies 2\pi =\theta$

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3 years ago

What's the answer and the work

Kryger [21]

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3 years ago

Calculate 19.25tons=___lbs.

Ket [755]

Answer:

19.25 tons = 38500 lbs

Step-by-step explanation:

We are to convert the following given amount of tons in pounds.

We know that, 1 ton = 2000 pounds. So using the ration method, we can convert 19.25 tons into pounds.

$\frac{1 ton}{19.25 tons} =\frac{2000 lbs}{x}$

$x = 2 0 0 0 \times 1 9 . 2 5$

$x = 3 8 5 0 0 lbs$

Therefore, 19.25 tons = 38500 lbs.

7 0

3 years ago

Read 2 more answers

Quadrilateral ABCD is inscribed in circle 0. Chords BA and CD are extended to intersect at point E. A tangent at B intersects li

irina [24]

Check the picture below.

let's notice the "white" ∡1 is an inscribed angle with an intercepted arc of (x-32), and the "green" ∡5 is also an inscribed angle with an intercepted arc of (2x).

the ∡6 and ∡2 are both external angles, however they intercepted two arcs, a "far arc" and a "near arc", thus we'll use the far arc - near arc formula, as you see in the picture, and we'll use the inscribed angle theorem for the other two.

$\bf \measuredangle 1=\cfrac{x-32}{2}\implies \measuredangle 1 =\cfrac{32}{2}\implies \measuredangle 1 = 16 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 5 =\cfrac{2x}{2}\implies \measuredangle 5 = x\implies \measuredangle 5 = 64 \\\\[-0.35em] ~\dotfill$

$\bf \measuredangle 2 = \cfrac{(2x+8)~~-~~(x-32)}{2}\implies \measuredangle 2=\cfrac{2x+8-x+32}{2} \\\\\\ \measuredangle 2=\cfrac{x+40}{2}\implies \measuredangle 2=\cfrac{104}{2}\implies \measuredangle 2=52 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 6=\cfrac{[(2x+8)+(x)]~~-~~(2x)}{2}\implies \measuredangle 6=\cfrac{3x+8-2x}{2}\implies \measuredangle 6=\cfrac{x+8}{2} \\\\\\ \measuredangle 6=\cfrac{72}{2}\implies \measuredangle 6=36$

7 0

3 years ago