A titration is defined as 'the process of determining the quantity of a substance A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalence is achieved (the equivalence point)'.
The Molarity of the HCl Solution requires the addition of 24.6 mL of titrant is 0.0836 M (to 3 significant figures)
<h3>What is Titrant?</h3>
A reagent solution of precisely known concentration that is added in titration
Given reaction HCl + NaOH ===> NaCl +
neutralization reaction
Note that the mole ratio is 1:1 meaning that 1 mole HCl reacts with 1 mole NaOH to produce 1 mole NaCl and 1 mole 
Find moles of NaOH used:
18.45 ml x 1 L/1000 ml x 0.085 mol/L = 0.002091 moles NaOH used
This meant that there must be 0.002091 moles of HCl present in the 25.0 mls.
We want to find the molarity (M) which is moles HCl/liter of solution. We know the moles, and we also know the liters of solution (25.0 mls x 1 L / 1000 mls = 0.025 liters)
M = 0.002091 moles HCl / 0.025 liters = 0.08364 M = 0.0836 M (to 3 significant figures)
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Isomers have the same molecular formula but they only differ in structure. So, when trans isomer is converted to cis isomer, you would expect a total mass of 25 mg exactly. So, the percent yield would be:
Percent yield = 5 mg/25 mg * 100 = <em>20%</em>
Depends how big the cracker is...
It could possibly be 3 atoms
You need the solubility of the LiCl in water at 20°C.
The solubilities are shown in tables. Many books contain those tables. You have to make sure that the solubility is shown in the same solvent and at the same temperature that you are going to prepare the solution.
In this case the solubility of LiCl in water at 20°C is 83.05 g of LiCl in 100 g of H2O. Check if your book and your teacher work with the same value.
Using 8.05 g LiCl / 100 g of water you get:
300 g of water * 83.05 g LiCl / 100 g of water = 249.15 g of LiCl.
Answer: 249.15 g of LiCl
Answer:
its pb because it has large number of electrons
hope it helps you