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Calculate the mass in grams of hydrogen chloride (HCl) that is formed when 5.6 L of molecular hydrogen, measured at TPE, reacts with an excess of gaseous molecular chlorine. MHCl = 36.5 g/mol
H2(g) + Cl2(g) → 2HCl(g)
Answer:
18.25g
Explanation:
The reaction equation is given as;
H₂ + Cl₂ → 2HCl
Given parameters:
Volume of hydrogen gas = 5.6L
The reaction occurs at STP.
Solution:
To solve this problem, let us find the number of moles of the hydrogen as;
At STP;
22.4L of a gas has 1 mole;
5.6L of Hydrogen as will have = 0.25mole
From the balanced reaction equation;
1 mole of H₂ will produce 2 mole of HCl
0.25 mole of H₂ will produce 2 x 0.25 = 0.5mole of HCl
The mass of HCl';
Mass of HCl = number of moles x molar mass
Mass of HCl = 0.5 x 36.5 = 18.25g