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4 years ago

5

Can someone solve this for me? Or explain it at least...? You don't have to give a full detailed answer, I just need simple answ

ers as a guide to this cause I'm really stuck. I'll give brainliest.

1 answer:

Snowcat [4.5K]4 years ago

5 0

Im not sure about this one but I think it would be a histogram because,
It shows the frequency of each student by showing how much or how high each student got on their quiz. On the left side going up and down is the frequency.
Part B: On bottom put the ranges of points like 0-10 11-20. <<Ex
Then, on the side, put the # of students!
Then draw the bars according to the data set.
Hope this helped! ;p
Srry if im wrong

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Please help fast its quiz. :(

dezoksy [38]

Answer:

What is the question??

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2 years ago

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kolbaska11 [484]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like

blsea [12.9K]

Answer:

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

(a) You like both of them.

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{2}{14} = 0.029$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{11}{14} = 0.629$

(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343$

(d) Redo (a)-(c) if a song can be replayed before all

(a) You like both of them. Would this be unusual?

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{3}{15} = 0.04$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{12}{15} = 0.64$

(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{15}+ \frac{12}{15} \times \frac{3}{15}= 0.32$

7 0

4 years ago

The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in

CaHeK987 [17]

Answer:

$\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

Step-by-step explanation:

The standard equation of the ellipse is

$\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)$

where, $(\alpha, \beta)$ is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, $(\alpha, \beta)=(-9,3)$ and major axis, $2a=24$ .

So, semi major axis, $a=24/2=12$ .

Now, focus of the ellipse is (-7,3).

Let $e$ be the eccentricity of the ellipse,

So, $e=\frac c a$

where $c$ is the distance between the center and focus of the ellipse.

By using the distance formula,

$c=\sqrt{(-9-(-7))^2+(3-3)^2}=2$

$\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)$

Again, the relationship among $a,b$ and $e$ is

$e=\sqrt{1-\frac{b^2}{a^2}$

$\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2}$ [from equation (ii)]

$\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144}$ [squaring on both the sides]

$\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}$

$\Rightarrow b^2=\frac{35}{36}\times144=140$

So, the value of square of semi-minir axis, $b^2=140$ .

Hence, from equation (i), the equation of required ellipse is standard form is

$\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1$

$\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

8 0

3 years ago

luvenia can row 4mph in still water. She takes as long to row 7 mi upstream as 21 mi downstream. how

xeze [42]

Answer:

The speed of the river is 2mph.

Step-by-step explanation:

I guess that we want to find the speed of the river.

First, remember the relation: speed*time = distance

If the speed of the river is Sr, when Luvenia moves downstream (in the same direction that the flow of the water) the total speed will be equal to the speed of Luvenia in still water plus the speed of the water:

Sd = 4mph + Sr

and at this speed, in a time T, she can move 21 miles, so we have:

Sd*T = (4mph + Sr)*T = 21 mi

When moving upstream, the speed will be:

Su = (4mph - Sr)

and in the same time T as before, she moves 7 miles, so we have the equation:

Su*T = (4mph - Sr)*T = 7 mi

Then we have two equations:

(4mph + Sr)*T = 21 mi

(4mph - Sr)*T = 7 mi

Now we can take the quotient of those two equations and get:

((4mph + Sr)*T)/((4mph - Sr)*T) = 21/7

The time T vanishes, and we can solve it for Sr.

(4mph + Sr)/(4mph - Sr) = 3

4mph + Sr = 3*(4mph - Sr) = 12mph - 3*Sr

4*Sr = 12mph - 4mph = 8mph

Sr = 8mph/4 = 2mph.

7 0

4 years ago