x > 7 x < 10
7 o---------------------o 10
This is not an empty set. x contains all of the values between 7 and 10.
F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
The correct answer is y ≥ 8
Step-by-step explanation:
In order to graph this, we must first solve the equation for y.
193 + y ≥ 201
y ≥ 8
Now that we have the solved version, we can graph on a number line. Draw a closed circle on the point 8 and then draw an arrow to the right to show that it is greater.
Answer:
r=7v−12
Step-by-step explanation:
Let's solve for r.
−8−2r=−7v−7v+16
Step 1: Add 8 to both sides.
−2r−8+8=−14v+16+8
−2r=−14v+24
Step 2: Divide both sides by -2.
−2r
−2
=
−14v+24
−2
r=7v−12
