Let's fix 2010 as the present time. According to basic equations in engineering economy,
F = P (1+i)^n where F is the future worth, P is the present worth, i is the interest rate and n is the number of years. Substituting the appropriate values,
F = $25,250 (1 + 0.068)^10 F = $48,750
If the student has payed for the $25,250, then he needs to pay $48750 - $25250 = $23,500 more.