3 years ago

NEED HELP ASAPPPPPPP

1 answer:

6 0

Wouldn’t it be 8 1/6....I think. Because if the product is a whole number you would just add the product to the remaining whatever. So it would all together be 8 1/6 - 1/6 = 8

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$\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
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