Answer:
3x³+16x+C
Step-by-step explanation:
Given the expression 9x²+16dx, we are to integrate the function.
The integral formula is expressed ad x^n+1/n+1
∫9x²+16 dx
= 9x³/3+ 16x^0+1/0+1
= 3x³ +16x¹ + C
Hence the integral of the function is 3x³+16x+C
cos theta = B/H
cos32=x/8.5
0.84= x/8.5
x=0.84 x 8.5
x= 7.14 cm.
Rewrite the equation as 4L+4W=P.
4L+4W=P
Subtract 4L from both sides of the equation.
4W=P−4L Divide each term by 4 and simplify.
W=P/4−L
No i don't think you do.
Explanation:
Hope this helps! :)
4(3x+y)^2
36x^2+24xy+4y^2
=9*4x^2+6*4xy+4y^2
=4(9x^2+6xy+y^2)
=4(3x+y)*(3x+y)
=4(3x+y)^2
Answer: 13
-4 - 9 = -13