Given the mean of 15 of them is 18 and the mean of the rest is 13
And the total numbers are 25
So,
First, we need to find the sum of all numbers
the mean of 15 of them is 18
so, the sum of the 15 numbers are = 18 * 15 = 270
The rest of the numbers = 25 - 15 = 10
the mean of the rest is 13
so, the sum of the rest = 13 * 10 = 130
so, the sum of all numbers = 270 + 130 = 400
so, the mean of the all numbers =
So, the answer is, mean = 16
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths.
Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday.
Jan - Friday
Feb - Monday
Mar - Monday
Apr - Thursday
May - Saturday
Jun - Tuesday
Jul - Thursday
Aug - Sunday
Sep - Wednesday
Oct - Friday
Nov - Monday
Dec - Wednesday
Now let's count how many times for each weekday, the 13th falls there.
Sunday - 1
Monday - 3
Tuesday - 1
Wednesday - 2
Thursday - 2
Friday - 2
Saturday - 1
The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc.
So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get:
Jan - Friday
Feb - Monday
Mar - Tuesday
Apr - Friday
May - Sunday
Jun - Wednesday
Jul - Friday
Aug - Monday
Sep - Thursday
Oct - Saturday
Nov - Tuesday
Dec - Thursday
And the weekday totals are:
Sunday - 1
Monday - 2
Tuesday - 2
Wednesday - 1
Thursday - 2
Friday - 3
Saturday - 1
And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year.
And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
the answer to this question is 55 cm
Answer: Y = 7x/2 -2
Step-by-step explanation:
Y intercept of -2 means there's a point at (0,-2).
Given the two points (4,12) and (0,-2), we can now find the slope
12-(-2)/4-0 = 14/4 = 7/2 which is the slope
so the equation is Y = 7x/2 -2
No, your answer are wrong (I assume that the question asks to simplify the roots). You can only remove (their square is placed in from of the root and multiplied by it) the numbers from the root that are squares, the lest must stay, like this:
no roots are among the factors, nothing can be removed
nothing can be removed
nothing can be removed
nothing can be removed
nothing can be removed
nothing can be removed
nothing can be removed
nothing can be removed
(47 is prime) nothing can be removed
