You just put two numbers that you can multiply to get the number and when you came divide anything else in the number then you circle it and that's one of the numbers
9514 1404 393
Answer:
(a) x^2/16 +y^2/9 = 1
Step-by-step explanation:
The form for the equation of an ellipse centered at the origin is ...
(x/(semi-x-axis))^2 +(y/(semi-y-axis))^2 = 1
The vertex values tell you the semi-x-axis is 4 units, and the semi-y-axis is 3 units. Then you have ...
(x/4)^2 +(y/3)^2 = 1
x^2/16 +y^2/9 = 1
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In case you don't remember that form, you can try any of the points in the equations. The equation that works will quickly become apparent.
Answer:
50 + 50 - 15 + 3
Step-by-step explanation:
Answer:
I think it is 8! Sorry if it's wrong!
Answer:
f(t) = 15.06 m
Step-by-step explanation:
The relationship between the height of the rocket and the time after launch, t. In seconds is given by :
![f(t) = - 4.9t ^ 2 + 16t + 2](https://tex.z-dn.net/?f=f%28t%29%20%3D%20-%204.9t%20%5E%202%20%2B%2016t%20%2B%202)
We need to find the maximum height the rocket will reach the ground.
When it reaches the ground,
f(t) = 0
So,
Maximum height,
f'(t) = 0
![-9.8t+16=0\\\\t=\dfrac{16}{9.8}\\\\t=1.63\ s](https://tex.z-dn.net/?f=-9.8t%2B16%3D0%5C%5C%5C%5Ct%3D%5Cdfrac%7B16%7D%7B9.8%7D%5C%5C%5C%5Ct%3D1.63%5C%20s)
Put t = 1.63 in equation (1).
![f(1.63) = - 4.9\times (1.63 ^ 2) + 16(1.63) + 2\\\\=15.06\ m](https://tex.z-dn.net/?f=f%281.63%29%20%3D%20-%204.9%5Ctimes%20%281.63%20%5E%202%29%20%2B%2016%281.63%29%20%2B%202%5C%5C%5C%5C%3D15.06%5C%20m)
So, the maximum height of the rocket is 15.06 m.