20 x 5 = 100 so just 18 x 5 = 90. 100 - 90= 10
the answer is 10%
The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:
Mean score of A = (sum of all scores) / 15
55 = (sum of all scores) / 15
sum of all scores in A = 825
The mean score for both classes is 76. Hence:
[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes
[825 + (sum of all scores in B)]/(15 + 29) = 76
sum of all scores in B = 2519
Mean score of B = (2519) / 29 = 86.86
The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
Find out more on equation at: brainly.com/question/13763238
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Answer:
21/4
Step-by-step explanation:
7 + 3²(12-8)
=> 7 + 9(4)
=> 7 + 36
=> 42
Equation:-
42 / (2x4)
=> 42/8
=> 21/4
Answer: the function that has the smaller minimum is g(x), and the cordinates are (0,3)
Step-by-step explanation:
We have a function for f(x) and a table for g(x)
first, quadratic functions are symmetrical.
This means that if the minimum/maximum is located at x = x0, we will have that:
f(x0 + A) = f(x0 - A)
For any real value of A.
Then when we look at the table, we can see that:
g(-1) = 7
g(0) = 3
g(1) = 7
then the minimum of g(x) must be at x = 0, and we can see that the minimum value of g(x) is 3.
Now let's analyze f(x).
When we have a quadratic equation of the shape.
y = a*x^2 + b*x + c
the minimum/maximum will be located at:
x = -b/2a
In our function we have:
a = 3
b = 6
then the minimum is at:
X = -6/2*3 = -1
f(-1) = 3*(-1)^2 + 6*-1 + 7 = 3 - 6 + 7 = 3 + 1 = 4
Then the function that has the smaller minimum is g(x), and the cordinates are (0,3)