Domain {-4, -2, 1, 2, 4, 5}
Range {-4, -3, -2, 1, 2, 4}
It is functional.
Step-by-step explanation:
f(x) = -16x² + 22x + 3
Factor:
f(x) = (8x + 1) (-2x + 3)
The x-intercepts are (-1/8, 0) and (3/2, 0).
The leading coefficient is negative, so the parabola points down. Therefore, the vertex is a maximum. The x-coordinate is halfway between the x-intercepts.
x = (-1/8 + 3/2) / 2
x = 11/16
f(11/16) = 169/16
So the vertex is at:
(11/16, 169/16)
Graph the x-intercepts and the vertex, then draw a curve through the 3 points.
Perimeter = sum of length of sides = 2( sum of the unequal sides)
length of (2, 4) to (5, 4) =
length of (5, 1) to (0, -1) =
Perimeter = 2(3 + 5.39) = 2 x 8.39 = 16.8 units
(x + y)^0 = 1
(x + y)^1 = x + y
(x + y)^2 = x^2 + 2x + y
(x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3
(x + y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
.
.
.
1
1 + 1
1 + 2 + 1
1 + 3 + 3 + 1
1 4 6 4 1
.
.
.
I hope I helped you.