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3 years ago

What is 0.6 as a fraction is simplest form

Mathematics

1 answer:

Darina [25.2K]3 years ago

4 0

0.6 is 6 tenths. 6/10 is the fraction form but you have to simplify so it becomes 3/5.

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What's the answer???

blsea [12.9K]

14/16 or anything like that

3 0

3 years ago

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What is the average of -30 -15 -20 55

defon

Answer:

-2.5

Step-by-step explanation:

-30 + (-15) + (-20) + 55 = -10. Then you divide it by how many numbers there are (4). Which equals - 2.5. If this is wrong, then round up to -3.

8 0

3 years ago

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The Yert family hires a landscaping company for 30 weeks. There are two companies to choose from. Green Lawns charges $1 for the

Nikolay [14]

Answer:

$133.77

I am pretty sure that this is the answer.

Step-by-step explanation:

1 + (1.25)^29 = 646.23

200 + (20 x 29) = 780

780 - 646.23 = 133.77

Tell me if I am wrong.

If right, please give me brainliest.

6 0

3 years ago

15 pts + brainliest to right/best answer

ZanzabumX [31]

Rewrite it in the form a^2 - b^2, where a = 2x and b = 5

(2x)^2 - 5^2

Use the Difference o Squares: a^2 - b^2 = (a + b)(a - b)

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3 years ago

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In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

3 years ago